Object.ReferenceEquals(Object, Object) 方法

定義

判斷指定的 Object 實例是否為同一實例。

public:
 static bool ReferenceEquals(System::Object ^ objA, System::Object ^ objB);
public static bool ReferenceEquals(object objA, object objB);
static member ReferenceEquals : obj * obj -> bool
Public Shared Function ReferenceEquals (objA As Object, objB As Object) As Boolean

參數

objA
Object

第一個比較的對象。

objB
Object

第二個比較物件。

傳回

trueobjA 是 與 objB 相同的實例,或 兩者皆 為零;否則, false

範例

以下範例用 ReferenceEquals 來判斷兩個物件是否為同一個實例。

object o = null;
object p = null;
object q = new Object();

Console.WriteLine(Object.ReferenceEquals(o, p));
p = q;
Console.WriteLine(Object.ReferenceEquals(p, q));
Console.WriteLine(Object.ReferenceEquals(o, p));

// This code produces the following output:
//   True
//   True
//   False
let o: obj = null
let mutable p: obj = null
let q = obj ()

printfn $"{Object.ReferenceEquals(o, p)}"
p <- q
printfn $"{Object.ReferenceEquals(p, q)}"
printfn $"{Object.ReferenceEquals(o, p)}"

// This code produces the following output:
//   True
//   True
//   False
Public Class App
    Public Shared Sub Main() 
        Dim o As Object = Nothing
        Dim p As Object = Nothing
        Dim q As New Object
        Console.WriteLine(Object.ReferenceEquals(o, p))
        p = q
        Console.WriteLine(Object.ReferenceEquals(p, q))
        Console.WriteLine(Object.ReferenceEquals(o, p))
    End Sub 
End Class 
' This code produces the following output:
'
' True
' True
' False
'

備註

與方法 Equals 及等號運算子不同,該 ReferenceEquals 方法無法被覆寫。 因此,如果你想測試兩個物件參考的相等性,且不確定方法的實作 Equals ,你可以呼叫該 ReferenceEquals 方法。

然而,在以下兩種情境中,該 ReferenceEquals 方法的返回值可能看起來異常:

  • 比較價值類型時, 若 objAobjB 是值型態,則在傳遞給 ReferenceEquals 方法前會先被框住。 這表示如果 和 objBobjA代表同一值型態的實例,ReferenceEquals該方法仍會回傳 false,如下範例所示。

    int int1 = 3;
    Console.WriteLine(Object.ReferenceEquals(int1, int1));
    Console.WriteLine(int1.GetType().IsValueType);
    
    // The example displays the following output:
    //       False
    //       True
    
    let int1 = 3
    printfn $"{Object.ReferenceEquals(int1, int1)}"
    printfn $"{int1.GetType().IsValueType}"
    
    // The example displays the following output:
    //       False
    //       True
    
    Public Module Example
       Public Sub Main
          Dim int1 As Integer = 3
          Console.WriteLine(Object.ReferenceEquals(int1, int1))
          Console.WriteLine(int1.GetType().IsValueType)
       End Sub
    End Module
    ' The example displays the following output:
    '       False
    '       True
    

    關於裝盒價值類型的資訊,請參見 「裝箱與開箱」。

  • 比較琴弦時, 若 objAobjB 是字串,則當字串被 interned 時,方法 ReferenceEquals 會回傳 true 。 它不會進行價值平等的檢驗。 以下範例中, s1s2 相等,因為它們是同一個被包含字串的兩個實例。 然而, s3s4 並不相等,因為雖然它們的字串值相同,但該字串並未被內化。

    String s1 = "String1";
    String s2 = "String1";
    Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2));
    Console.WriteLine("{0} interned: {1}", s1,
                      String.IsNullOrEmpty(String.IsInterned(s1)) ? "No" : "Yes");
    
    String suffix = "A";
    String s3 = "String" + suffix;
    String s4 = "String" + suffix;
    Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4));
    Console.WriteLine("{0} interned: {1}", s3,
                      String.IsNullOrEmpty(String.IsInterned(s3)) ? "No" : "Yes");
    
    // The example displays the following output:
    //       s1 = s2: True
    //       String1 interned: Yes
    //       s3 = s4: False
    //       StringA interned: No
    
    open System
    
    let s1 = "String1"
    let s2 = "String1"
    printfn $"s1 = s2: {Object.ReferenceEquals(s1, s2)}"
    printfn $"""{s1} interned: {if String.IsNullOrEmpty(String.IsInterned s1) then "No" else "Yes"}"""
    
    let suffix = "A"
    let s3 = "String" + suffix
    let s4 = "String" + suffix
    printfn $"s3 = s4: {Object.ReferenceEquals(s3, s4)}"
    printfn $"""{s3} interned: {if String.IsNullOrEmpty(String.IsInterned s3) then "No" else "Yes"}"""
    
    // The example displays the following output:
    //       s1 = s2: True
    //       String1 interned: Yes
    //       s3 = s4: False
    //       StringA interned: No
    
    Module Example
       Public Sub Main()
          Dim s1 As String = "String1"
          Dim s2 As String = "String1"
          Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2))
          Console.WriteLine("{0} interned: {1}", s1, 
                            If(String.IsNullOrEmpty(String.IsInterned(s1)), "No", "Yes"))
    
          Dim suffix As String = "A"
          Dim s3 = "String" + suffix
          Dim s4 = "String" + suffix
          Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4))
          Console.WriteLine("{0} interned: {1}", s3, 
                            If(String.IsNullOrEmpty(String.IsInterned(s3)), "No", "Yes"))
       End Sub
    End Module
    ' The example displays the following output:
    '       s1 = s2: True
    '       String1 interned: Yes
    '       s3 = s4: False
    '       StringA interned: No
    

    關於弦中介的更多資訊,請參見 String.IsInterned

適用於

另請參閱