Object.ReferenceEquals(Object, Object) 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
判斷指定的 Object 實例是否為同一實例。
public:
static bool ReferenceEquals(System::Object ^ objA, System::Object ^ objB);
public static bool ReferenceEquals(object objA, object objB);
static member ReferenceEquals : obj * obj -> bool
Public Shared Function ReferenceEquals (objA As Object, objB As Object) As Boolean
參數
- objA
- Object
第一個比較的對象。
- objB
- Object
第二個比較物件。
傳回
true 若 objA 是 與 objB 相同的實例,或 兩者皆 為零;否則, false。
範例
以下範例用 ReferenceEquals 來判斷兩個物件是否為同一個實例。
object o = null;
object p = null;
object q = new Object();
Console.WriteLine(Object.ReferenceEquals(o, p));
p = q;
Console.WriteLine(Object.ReferenceEquals(p, q));
Console.WriteLine(Object.ReferenceEquals(o, p));
// This code produces the following output:
// True
// True
// False
let o: obj = null
let mutable p: obj = null
let q = obj ()
printfn $"{Object.ReferenceEquals(o, p)}"
p <- q
printfn $"{Object.ReferenceEquals(p, q)}"
printfn $"{Object.ReferenceEquals(o, p)}"
// This code produces the following output:
// True
// True
// False
Public Class App
Public Shared Sub Main()
Dim o As Object = Nothing
Dim p As Object = Nothing
Dim q As New Object
Console.WriteLine(Object.ReferenceEquals(o, p))
p = q
Console.WriteLine(Object.ReferenceEquals(p, q))
Console.WriteLine(Object.ReferenceEquals(o, p))
End Sub
End Class
' This code produces the following output:
'
' True
' True
' False
'
備註
與方法 Equals 及等號運算子不同,該 ReferenceEquals 方法無法被覆寫。 因此,如果你想測試兩個物件參考的相等性,且不確定方法的實作 Equals ,你可以呼叫該 ReferenceEquals 方法。
然而,在以下兩種情境中,該 ReferenceEquals 方法的返回值可能看起來異常:
比較價值類型時, 若
objA和objB是值型態,則在傳遞給 ReferenceEquals 方法前會先被框住。 這表示如果 和objB都objA代表同一值型態的實例,ReferenceEquals該方法仍會回傳false,如下範例所示。int int1 = 3; Console.WriteLine(Object.ReferenceEquals(int1, int1)); Console.WriteLine(int1.GetType().IsValueType); // The example displays the following output: // False // Truelet int1 = 3 printfn $"{Object.ReferenceEquals(int1, int1)}" printfn $"{int1.GetType().IsValueType}" // The example displays the following output: // False // TruePublic Module Example Public Sub Main Dim int1 As Integer = 3 Console.WriteLine(Object.ReferenceEquals(int1, int1)) Console.WriteLine(int1.GetType().IsValueType) End Sub End Module ' The example displays the following output: ' False ' True關於裝盒價值類型的資訊,請參見 「裝箱與開箱」。
比較琴弦時, 若
objA和objB是字串,則當字串被 interned 時,方法 ReferenceEquals 會回傳true。 它不會進行價值平等的檢驗。 以下範例中,s1和s2相等,因為它們是同一個被包含字串的兩個實例。 然而,s3和s4並不相等,因為雖然它們的字串值相同,但該字串並未被內化。String s1 = "String1"; String s2 = "String1"; Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)); Console.WriteLine("{0} interned: {1}", s1, String.IsNullOrEmpty(String.IsInterned(s1)) ? "No" : "Yes"); String suffix = "A"; String s3 = "String" + suffix; String s4 = "String" + suffix; Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)); Console.WriteLine("{0} interned: {1}", s3, String.IsNullOrEmpty(String.IsInterned(s3)) ? "No" : "Yes"); // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: Noopen System let s1 = "String1" let s2 = "String1" printfn $"s1 = s2: {Object.ReferenceEquals(s1, s2)}" printfn $"""{s1} interned: {if String.IsNullOrEmpty(String.IsInterned s1) then "No" else "Yes"}""" let suffix = "A" let s3 = "String" + suffix let s4 = "String" + suffix printfn $"s3 = s4: {Object.ReferenceEquals(s3, s4)}" printfn $"""{s3} interned: {if String.IsNullOrEmpty(String.IsInterned s3) then "No" else "Yes"}""" // The example displays the following output: // s1 = s2: True // String1 interned: Yes // s3 = s4: False // StringA interned: NoModule Example Public Sub Main() Dim s1 As String = "String1" Dim s2 As String = "String1" Console.WriteLine("s1 = s2: {0}", Object.ReferenceEquals(s1, s2)) Console.WriteLine("{0} interned: {1}", s1, If(String.IsNullOrEmpty(String.IsInterned(s1)), "No", "Yes")) Dim suffix As String = "A" Dim s3 = "String" + suffix Dim s4 = "String" + suffix Console.WriteLine("s3 = s4: {0}", Object.ReferenceEquals(s3, s4)) Console.WriteLine("{0} interned: {1}", s3, If(String.IsNullOrEmpty(String.IsInterned(s3)), "No", "Yes")) End Sub End Module ' The example displays the following output: ' s1 = s2: True ' String1 interned: Yes ' s3 = s4: False ' StringA interned: No關於弦中介的更多資訊,請參見 String.IsInterned。